You are correct that the freq is same for both signals.
Now all you need is volts/division for the 2 signals, which is displayed. And the v/div is different for both signals.
Here's what you are looking at: The channel 1 signal is a sine wave being fed into a differential amplifier, which is being overdriven to the point of clipping, which produced the square wave output on Channel 2.
But it is all there, 2 sets of volts/div and (of course) one set of time/div (and 1/time equals freq.)
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